The Simplifier

Example Two

2. Evaluate: 1 of 1 – (1 – 1) + 1 ÷ 1 x 1

Start with the bracket:
1 of 1 – (1 – 1) + 1 ÷ 1 x 1 = 1 of 1 – 0 + 1 ÷ 1 x 1

Next is to handle the of (if it exists):
1 of 1 – 0 + 1 ÷ 1 x 1 = 1 – 0 + 1 ÷ 1 x 1

Next is to deal with Division (if it exists):
1 – 0 + 1 ÷ 1 x 1 = 1 – 0 + 1  x 1

Next is to handle Multiplication (if it exists)
1 – 0 + 1 x 1 = 1 – 0 + 1

Next is to consider Addition & Subtraction (if it exists)
1– 0 + 1 = 1 + 1 = 2

Keynote

It is not a must that all the operators must exist in one problem but the sequence is always followed while the operator not in the operators are skipped to the next available one!