The Simplifier

Example Two 2. Evaluate: 1 of 1 – (1 – 1) + 1 ÷ 1 x 1 Start with the bracket: 1 of 1 – (1 – 1) + 1 ÷ 1 x 1 = 1 of 1 – 0 + 1 ÷ 1 x 1 Next is to handle the of ( if it exists ): 1 of 1 – 0 + 1 ÷ 1 x 1 = 1 – 0 + 1 ÷ 1 x 1 Next is to deal with Division ( if it exists ): 1 – 0 + 1 ÷ 1 x 1 = 1 – 0 + 1  x 1 Next is to handle Multiplication ( if it exists ) 1 – 0 + 1 x 1 = 1 – 0 + 1 Next is to consider Addition & Subtraction ( if it exists ) 1– 0 + 1 = 1 + 1 = 2 Keynote It is not a must that all the operators must exist in one problem but the sequence is always followed while the operator not in the operators are skipped to the next available one!